12c^2+29c+15=

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Solution for 12c^2+29c+15= equation:


Simplifying
12c2 + 29c + 15 = 0

Reorder the terms:
15 + 29c + 12c2 = 0

Solving
15 + 29c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + 3c)(3 + 4c) = 0

Subproblem 1

Set the factor '(5 + 3c)' equal to zero and attempt to solve: Simplifying 5 + 3c = 0 Solving 5 + 3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 3c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 3c = 0 + -5 3c = 0 + -5 Combine like terms: 0 + -5 = -5 3c = -5 Divide each side by '3'. c = -1.666666667 Simplifying c = -1.666666667

Subproblem 2

Set the factor '(3 + 4c)' equal to zero and attempt to solve: Simplifying 3 + 4c = 0 Solving 3 + 4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 4c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 4c = 0 + -3 4c = 0 + -3 Combine like terms: 0 + -3 = -3 4c = -3 Divide each side by '4'. c = -0.75 Simplifying c = -0.75

Solution

c = {-1.666666667, -0.75}

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